StarGeek edit: Split from this old thread (https://exiftool.org/forum/index.php?msg=66298)
I'm trying to change only the date from an image and tried something similar to the abome mentioned, but it doesn't work.
exiftool -DateTimeOriginal"<${DateTimeOriginal;s/ 20240908/ .*/}" "_A9_7062_ILCE-9_E 17-28mm F2.8-2.8.ARW"
How can I do that?
Thanks!
Marcio
Your RegEx substitution is incorrect. You are using a simple string of numbers for your date and requiring a leading space. The date format is "Year:Month:Day Hour:Minute:Second", e.g. "2024:09:09 12:00:00". And you don't have a replacement value.
To change only the date, your command would be something like this
exiftool "-DateTimeOriginal<${DateTimeOriginal;s/2024:09:08/2022:03:14/}" "_A9_7062_ILCE-9_E 17-28mm F2.8-2.8.ARW"
But a Shift Time operation is usually better in cases like this. The command for that would be along these lines
exiftool -DateTimeOriginal±="Year:Month:Day 0" /path/to/files/
Replace ± with either a plus or minus sign, depending upon which way you want to shift the time. Replace each of Year/Month/Day with the amount you want to shift by, using 0 if you don't want to shift that at all. The trailing (space)0 (which represents the hour) is required because otherwise ShiftTime operation default to shifting hours.