ExifTool Forum

I am using the following exiftool executable and getting the attached csv output. Most everything (labels and data) are lumped together into Column A. How do I get this to be exif field names in Row 1 and the associated data in row 2? Or Exif field names in column A and data in column B?


exiftool(-a -m -u -w csv).exe

Thanks!

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You forgot the -csv option.  Try this:

exiftool(-a -m -u -w csv -csv).exe

- Phil

Hi Phil,
I am not getting a "Error: File not found - csv" message.

Watch the order of the arguments.

I followed what you suggested, but added a -k to see the data. Took out the -w as it was throwing an error when used with -csv as well. Field names and data show up in command line but is preceded by that same error message. Followed by "1 images files read", "1 files could not be read".

exiftool(-k -a -m -u csv -csv).exe

The -w option requires an argument giving the file extension, so it must appear as -w csv

- Phil

Got it. So leaving out the -w for now, because I'm still having issues. I've now used these arguments, it generates data in the command line view, but after pressing enter, no .csv file is saved to the location.

exiftool(-k -a -m -u -csv).exe

Ah, right:

> exiftool a.jpg -k -a -m -u -csv -w csv
Sorry, -w may not be combined with -csv

This is because of the way -csv functions on multiple files.

Typically the -csv option is used only for multiple files, but the -w option is designed to have one output file for each source file.

Are you doing this on one file at a time?  If doing it for multiple files, where do you want the output file and what do you want it named?  For this you could use a Windows .bat file and redirect the output to a file.

- Phil

I've been testing with 1 input file, but will be eventually using it for multiple input files, written out to 1 csv file.

So for multiple files, I should be able to drop a folder of images on a .bat file, with the below code, and have it export to a csv right?

exiftool.exe -k -a -m -u -csv > output.csv

When I do the above a csv is generated but is blank.

You need to add %* so the filenames get passed.

See this StackOverflow question (https://stackoverflow.com/questions/16144716/what-does-mean-in-a-batch-file).

Yes! Thank you Phil and StarGeek! Much appreciated.